Southern New Hampshire University

PHY215: Physics I

A study guide to SNHU's PHY 215, the calculus-based mechanics course covering Newton's laws, linear systems and rotation.

Updated October 2026 · 5 min read

PHY 215 at Southern New Hampshire University is the first calculus-based physics course.

The catalog says students cover the basic principles of mechanics, apply Newton's laws to linear systems, analyze physical phenomena in rotating systems, and solve complex problems that connect mechanics to real-world phenomena.

It is the course where physics stops being formula lookup and becomes modeling. Students are expected to set up a situation, choose a principle, use calculus where motion changes continuously, and interpret the result.

Course at a Glance

ItemDetails
UniversitySouthern New Hampshire University
Course codePHY 215
Credits3
Maths levelCalculus-based
PrerequisiteMAT 225 Calculus I, completed or taken concurrently (per the SNHU catalog)
Next coursePHY 216 Physics II (continuation)

What PHY 215 Covers

Area (from the catalog)What it involves
Newton's laws for linear systemsFree-body diagrams, net force, friction, tension, connected objects
Rotating systemsAngular motion, torque, moment of inertia, rotational dynamics
Further physical phenomenaApplying mechanical principles to additional situations in the course materials
Complex problems and real-world linksMulti-step problems that combine principles

Energy and momentum methods usually appear in a mechanics course of this kind; confirm the exact order and scope in your module list.

Where Calculus Enters, with Worked Examples

Kinematics from a Position Function

If position is given as a function of time, velocity is its derivative and acceleration is the derivative of velocity.

Example: x(t) = 3t² + 2t (meters, seconds). v(t) = dx/dt = 6t + 2, so at t = 2 s, v = 14 m/s. a(t) = dv/dt = 6 m/s², constant.

Rotational Dynamics

Torque plays the role of force and moment of inertia the role of mass: τ = Iα.

Example: A solid disc of mass 2.0 kg and radius 0.50 m has I = ½MR² = 0.5 x 2.0 x 0.25 = 0.25 kg m². A torque of 1.0 N m gives α = τ/I = 4.0 rad/s².

Linear Systems

For two blocks connected by a string, write Newton's second law for each, then use the shared acceleration to solve the pair. Keep tension the same on both sides of an ideal string.

Typical Assignments and How to Approach Them

Assignment typeWhat it testsHow to approach it
Problem setsMulti-step modelingDiagram, coordinate system, equations, symbolic solution, numbers last
Lab work (if part of your course)Measurement and analysisRecord uncertainties, plot data and compare with theory
Quizzes and testsFluency under timePractice mixed problems without notes
Written explanationsConceptual understandingName the principle and explain why it applies

Where Students Get Stuck

Study Tips for PHY 215

  1. Build a table pairing linear and rotational quantities and relations.
  2. Check dimensions: every term in an equation must have the same units.
  3. Test limits: ask what your formula gives when mass or time becomes very large or very small.
  4. Practice Calculus I techniques alongside the physics so neither slows you down.
  5. Write a sentence interpreting each answer.

Worked Example: Connected Blocks

Two-body problems show the whole method of the course: separate diagrams, one equation per body, shared constraint.

Example: A 4.0 kg block on a frictionless table is tied by a light string over a pulley to a hanging 2.0 kg mass. Take the direction of motion as positive. Table block: T = 4.0a. Hanging block: 2.0g - T = 2.0a. Add the two equations: 2.0g = 6.0a, so a = (2.0 x 9.8) / 6.0, about 3.3 m/s². Then T = 4.0 x 3.3, about 13 N. Check: T is less than the hanging weight (19.6 N), as it must be because the hanging block accelerates downward.

Work, Energy and Power

Many mechanics courses move from forces to energy because energy methods avoid solving for acceleration. Check your course outline for where the topic sits, but make sure you can handle these relationships.

QuantityExpressionCalculus link
Work by a variable forceW = integral of F dxArea under a force-position graph
Kinetic energy½mv²Work-energy theorem
PowerP = dW/dtRate of change of work

Habits That Raise Accuracy

Calculus-based mechanics problems are long, so small habits matter more than clever tricks.

When a problem includes a variable force, say F(x) = 3x newtons, remember that work is the integral of F dx. Between x = 0 and x = 2 m that gives 1.5 x 2² = 6 J.

How We Help with PHY 215

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Frequently Asked Questions

Is PHY 215 calculus-based?

Yes. The catalog lists Calculus I (MAT 225) as completed or concurrent.

What does PHY 215 cover?

Basic principles of mechanics, Newton's laws for linear systems, rotating systems and complex real-world problems.

What is the difference between PHY 150 and PHY 215?

PHY 150 is algebra-based; PHY 215 uses calculus and is the start of the STEM physics sequence.

Which course follows PHY 215?

PHY 216 Physics II, which the catalog describes as its continuation.

Is there a separate lab?

The catalog lists a PHY 215 lab (PHY 215L) as a prerequisite to PHY 216; check your degree plan for how it is scheduled.

Can you help me check my solution?

Yes. Send it with the question and we show where the reasoning, calculus or units go wrong.