A skateboarder travelling on a quarter pipe surface that has a radius of 3m. Initially, he is travel with speed 2.5 m/s, when he dropped a distance of Im, the speed is defined by v = (2.5 -0.15x) m/s. The equation of the skateboarder’s path is that of a quarter circle is given by y=s – Vr2 – x2 where r is radius of the circle. The radius of curvature of the path at location A is given, p = 3.5 m. (a) (b) Find the coordinate of skateboarder and the direction of his velocity at this location A. Determine the magnitude of the skateboarder’s acceleration at this instant. What happen to the normal acceleration when the skateboarder is moving in a rectilinear motion? Prove your answer with mathematical equation. y=r-p2 – x?
